接觸 Python 不久,看到很多人寫2048,自己也搗鼓了一個(gè),主要是熟悉Python語(yǔ)法。
程序使用Python3 寫的,代碼150行左右,基于控制臺(tái),方向鍵使用輸入字符模擬。
演示圖片
2048.py
# -*- coding:UTF-8 -*-
#! /usr/bin/python3
import random
v = [[0, 0, 0, 0],
[0, 0, 0, 0],
[0, 0, 0, 0],
[0, 0, 0, 0]]
def display(v, score):
'''顯示界面
'''
print('{0:4} {1:4} {2:4} {3:4}'.format(v[0][0], v[0][1], v[0][2], v[0][3]))
print('{0:4} {1:4} {2:4} {3:4}'.format(v[1][0], v[1][1], v[1][2], v[1][3]))
print('{0:4} {1:4} {2:4} {3:4}'.format(v[2][0], v[2][1], v[2][2], v[2][3]))
print('{0:4} {1:4} {2:4} {3:4}'.format(v[3][0], v[3][1], v[3][2], v[3][3]), ' Total score: ', score)
def init(v):
'''隨機(jī)分布網(wǎng)格值
'''
for i in range(4):
v[i] = [random.choice([0, 0, 0, 2, 2, 4]) for x in range(4)]
def align(vList, direction):
'''對(duì)齊非零的數(shù)字
direction == 'left':向左對(duì)齊,例如[8,0,0,2]左對(duì)齊后[8,2,0,0]
direction == 'right':向右對(duì)齊,例如[8,0,0,2]右對(duì)齊后[0,0,8,2]
'''
# 移除列表中的0
for i in range(vList.count(0)):
vList.remove(0)
# 被移除的0
zeros = [0 for x in range(4 - len(vList))]
# 在非0數(shù)字的一側(cè)補(bǔ)充0
if direction == 'left':
vList.extend(zeros)
else:
vList[:0] = zeros
def addSame(vList, direction):
'''在列表查找相同且相鄰的數(shù)字相加, 找到符合條件的返回True,否則返回False,同時(shí)還返回增加的分?jǐn)?shù)
direction == 'left':從右向左查找,找到相同且相鄰的兩個(gè)數(shù)字,左側(cè)數(shù)字翻倍,右側(cè)數(shù)字置0
direction == 'right':從左向右查找,找到相同且相鄰的兩個(gè)數(shù)字,右側(cè)數(shù)字翻倍,左側(cè)數(shù)字置0
'''
score = 0
if direction == 'left':
for i in [0, 1, 2]:
if vList[i] == vList[i+1] != 0:
vList[i] *= 2
vList[i+1] = 0
score += vList[i]
return {'bool':True, 'score':score}
else:
for i in [3, 2, 1]:
if vList[i] == vList[i-1] != 0:
vList[i-1] *= 2
vList[i] = 0
score += vList[i-1]
return {'bool':True, 'score':score}
return {'bool':False, 'score':score}
def handle(vList, direction):
'''處理一行(列)中的數(shù)據(jù),得到最終的該行(列)的數(shù)字狀態(tài)值, 返回得分
vList: 列表結(jié)構(gòu),存儲(chǔ)了一行(列)中的數(shù)據(jù)
direction: 移動(dòng)方向,向上和向左都使用方向'left',向右和向下都使用'right'
'''
totalScore = 0
align(vList, direction)
result = addSame(vList, direction)
while result['bool'] == True:
totalScore += result['score']
align(vList, direction)
result = addSame(vList, direction)
return totalScore
def operation(v):
'''根據(jù)移動(dòng)方向重新計(jì)算矩陣狀態(tài)值,并記錄得分
'''
totalScore = 0
gameOver = False
direction = 'left'
op = input('operator:')
if op in ['a', 'A']: # 向左移動(dòng)
direction = 'left'
for row in range(4):
totalScore += handle(v[row], direction)
elif op in ['d', 'D']: # 向右移動(dòng)
direction = 'right'
for row in range(4):
totalScore += handle(v[row], direction)
elif op in ['w', 'W']: # 向上移動(dòng)
direction = 'left'
for col in range(4):
# 將矩陣中一列復(fù)制到一個(gè)列表中然后處理
vList = [v[row][col] for row in range(4)]
totalScore += handle(vList, direction)
# 從處理后的列表中的數(shù)字覆蓋原來(lái)矩陣中的值
for row in range(4):
v[row][col] = vList[row]
elif op in ['s', 'S']: # 向下移動(dòng)
direction = 'right'
for col in range(4):
# 同上
vList = [v[row][col] for row in range(4)]
totalScore += handle(vList, direction)
for row in range(4):
v[row][col] = vList[row]
else:
print('Invalid input, please enter a charactor in [W, S, A, D] or the lower')
return {'gameOver':gameOver, 'score':totalScore}
# 統(tǒng)計(jì)空白區(qū)域數(shù)目 N
N = 0
for q in v:
N += q.count(0)
# 不存在剩余的空白區(qū)域時(shí),游戲結(jié)束
if N == 0:
gameOver = True
return {'gameOver':gameOver, 'score':totalScore}
# 按2和4出現(xiàn)的幾率為3/1來(lái)產(chǎn)生隨機(jī)數(shù)2和4
num = random.choice([2, 2, 2, 4])
# 產(chǎn)生隨機(jī)數(shù)k,上一步產(chǎn)生的2或4將被填到第k個(gè)空白區(qū)域
k = random.randrange(1, N+1)
n = 0
for i in range(4):
for j in range(4):
if v[i][j] == 0:
n += 1
if n == k:
v[i][j] = num
break
return {'gameOver':gameOver, 'score':totalScore}
init(v)
score = 0
print('Input:W(Up) S(Down) A(Left) D(Right), press
.')
while True:
display(v, score)
result = operation(v)
if result['gameOver'] == True:
print('Game Over, You failed!')
print('Your total score:', score)
else:
score += result['score']
if score >= 2048:
print('Game Over, You Win!!!')
print('Your total score:', score)
以上所述就是本文給大家分享的全部代碼了,希望能夠?qū)Υ蠹覍W(xué)習(xí)Python有所幫助。
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